37.19=27t-4.9t^2

Solution for 37.19=27t-4.9t^2 equation:

37.19=27t-4.9t^2

We move all terms to the left:

37.19-(27t-4.9t^2)=0

We get rid of parentheses

4.9t^2-27t+37.19=0

a = 4.9; b = -27; c = +37.19;
Δ = b2-4ac
Δ = -272-4·4.9·37.19
Δ = 0.076000000000022
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{0.076000000000022}}{2*4.9}=\frac{27-\sqrt{0.076000000000022}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{0.076000000000022}}{2*4.9}=\frac{27+\sqrt{0.076000000000022}}{9.8}
$